Question

acontainer is filled whith mercury to alevel of 10m whit water to alevel of 8m and whit oil to alevel of 5m the densities oil ,water and mercury are 0.8g/cm³,1g/cm³ and 13.6g/cm³ calculate the total pressure exerted by the liquids at the base​

Answer 1

1450.4 KN
`m^(2)`

Step-by-step explanation:

Pressure = ρhg

where: ρ is the density of the liquid, h is the height and g the force of gravity.

Total pressure exerted by the liquids at the base = Pressure of oil + Pressure of water + Pressure of mercury

So that,

i. Pressure of oil = ρhg

(ρ = 0.8 g/cm³ = 800 kg/m³)

= 800 x 5 x 9.8

= 39200

Pressure of oil = 39200 N
`m^(2)`

ii. Pressure of water = ρhg

(ρ = 1 g/cm³ = 1000 kg/m³)

= 1000 x 8 x 9.8

= 78400

Pressure of water = 78400 N
`m^(2)`

ii. Pressure of mercury = ρhg

(ρ = 13.6 g/cm³ = 13600 kg/m³)

= 13600 x 10 x 9.8

= 1332800

Pressure of mercury = 1332800 N
`m^(2)`

So that,

Total pressure exerted by the liquids at the base = 39200 + 78400 + 1332800

= 1450400

= 1450.4 KN
`m^(2)`

Total pressure exerted by the liquids at the base is 1450.4 KN
`m^(2)`.