Question

Please help me with this.


And show all work as well ASAP!!​

Answer 1

Answer: The partial pressure of oxygen is 187 torr.

Step-by-step explanation:

According to Raoult's law, the partial pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the total pressure.

`p_1=x_1p_(total)`

where, x = mole fraction

`p_(total)` = total pressure

`x_(oxygen)=\frac{\text {moles of oxygen}}{\text {total moles}}`,

`x_(oxygen)=(3.0)/(12.33)=0.243`,

`p_(oxygen)=0.243* 770torr=187torr`

Thus the partial pressure of oxygen is 187 torr.