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How many grams of sucrose(342g/mole) are needed to make 1L of 1M solution?

User Runwuf
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1 Answer

4 votes

Answer:

342grams

Step-by-step explanation:

The mass in grams needed to make a solution can be calculated by first calculating its molarity using the below formula;

Molarity = number of moles (mol)/volume (L)

number of moles (n) = volume × molarity

n = 1M × 1L

n = 1mol.

Using mole = mass ÷ molar mass

Molar mass of sucrose (C12H22O11) = 342g/mol.

1 = mass/342

mass = 342 × 1

mass = 342grams of sucrose are needed to make 1L of 1M solution.

User Nateyolles
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