Question

How much energy is required to raise the temperature of 3 kg of iron from 20°

C to 25°C? Use the table below and this equation: Q = mcAT.

Answer 1

Option C (6750 J) is the appropriate response.

Step-by-step explanation:

The given values are:

Mass of iron,

m = 3 kg

Specific heat capacity,

`c_A` = 0.450

Temperature,

T =
`25-20`

=
`5^(\circ)C`

Now,

⇒
`Q=mc_A T`

On substituting the values, we get

⇒
`=3* 0.450* 5`

⇒
`=6.75`

i.e,

⇒
`=6750 \ J`