Question

Help!!!!!!!!!find the equation of the linear function q(16)=1 that is parralel to f(x)=1/3x+39

It wants it in slope intercept form

Answer 1

`q(x)= (1)/(3) x -(13)/(3)`

Explanation:

So you have (16, 1)

When two linear functions are parallel, they have the same slope.

So function q also has a slope of 1/3x. You have a set of points so you can plug them in a slope intercept equation to find b.

y= mx+b

m= slope

y= y-intercept

1= 1/3(16) +b

1 - (16/3) = b

b= -13/3

so then,
`y= (1)/(3) x -(13)/(3)`