Question

Determine the mass of CO2 formed if 15 grams of C4H10

Answer 1

`m_(CO_2)=45gCO_2`

Step-by-step explanation:

Hello there!

In this case, since the combustion of butane is:

`C_4H_(10)+(13)/(2) O_2\rightarrow 4CO_2+5H_2O`

Thus, since the molar mass of butane is 58.12 g/mol and that of carbon dioxide is 44.01 g/mol, we obtain the following mass of CO2 product:

`m_(CO_2)=15gC_4H_(10)*(1molC_4H_(10))/(58.12gC_4H_(10)) *(4molCO_2)/(1molC_4H_(10)) *(44.01gCO_2)/(1molCO_2) \\\\m_(CO_2)=45gCO_2`

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