Question

What is the work when a gas expands from 0.666 L to 2.334 L against an external pressure of 2.07 atm?

Answer 1

work = 3.45 Joules

Step-by-step explanation:

Work from the 1st Law of Thermodynamics is PΔV in the equation of internal energy => ΔE = ΔH + PΔV.

Therefore, work = PΔV = 2.07atm·(2.334L - 0.666L) = 3.45 L·atm = 3.45 Joules