Question

A sample of gas at 62.0°C occupies a volume of 4.80 L at a pressure of 2.90 atm. How many

moles of gas are contained in the sample?

Answer 1

Answer: 37.01 moles (mol) of gas

Explanation:Use PV=nRT

which is also equal to n=PV/RT

P=2.90

V= 4.80

R = 8.31 (R will always be the same in any equation)

T= 62.0

2.90 x 4.80= 13.92 / 8.31 x 62= 515.22

13.92/13.92=515.22/13.92

n= 37.01 mol