Question

Natalia bought 4 boxes of pencils and 9 reams of paper for 75$. Ronnie by eight boxes of pencils and five reams of paper for 67.

Answer 1

The cost of one box of pencils is $4.38 and the cost of one ream of paper is $6.38.

Step-by-step explanation:

To solve this problem, we can set up a system of equations. Let's use 'x' to represent the cost of one box of pencils and 'y' to represent the cost of one ream of paper.

From the information given, we have the following equations:

4x + 9y = 75 (equation 1)

8x + 5y = 67 (equation 2)

We can solve this system of equations using either elimination or substitution method. Let's use the elimination method:

Multiplying equation 1 by 5 and equation 2 by 9, we get:

20x + 45y = 375 (equation 3)

72x + 45y = 603 (equation 4)

Subtracting equation 3 from equation 4, we get:

72x - 20x = 603 - 375

52x = 228

Dividing both sides by 52, we get:

x = 4.38

Substituting the value of x into equation 1, we get:

4(4.38) + 9y = 75

17.52 + 9y = 75

9y = 57.48

Dividing both sides by 9, we get:

y = 6.38

Therefore, the cost of one box of pencils is $4.38 and the cost of one ream of paper is $6.38.

Answer 2

Answer:a box of pencil cost=$4.395

And a ream of paper cost=$6.38

Step-by-step explanation:

Let the cost of box of pencil be represented as p

And the cost of ream of paper be represented as r

Such that

4 boxes of pencils and 9 reams of paper costing 75$ be represented as

4p+9r=75-----equation 1

Also, eight boxes of pencils and five reams of paper for 67 be represented as

8p + 5r=67------equation 2

Solving

4p+9r=75-----equation 1

8p + 5r=67------equation 2

By elimination method, multiply equation 1 by 2 and equation 2 by 1

8p +18r=150---equation 3

8p+5r=67----equation 4

Subtracting equation 4 from equation 3

13r=83

r=83/13

r=6.38

Putting the value of r=6.38 in equation 1 to solve for p, we have

4p+9r=75

4p+9(6.38)=75

4p+57.42= 75

4p=75-57.42

4p=17.58

p=17.58/4

p=4.395.

Therefore a box of pencil cost=$4.395

And a ream of paper cost=$6.38