Question

Grams to Grams

1N2 + 3H2 -->2NH3
If you produced 34.06g of NH3 assuming excess N2 how many grams of H2 was used?

Answer 1

grams H₂(g) = 6.11 grams H₂(g) used

Step-by-step explanation:

Convert all given values to moles (if not already in moles), solve by rxn ratios and then convert moles to needed dimensions.

N₂(g) + 3H₂(g) => 2NH₃(g)

excess ? 34.6g/17g/mole = 2.04 moles

moles of H₂(g) needed = 3/2(2.04)moles = 3.05 moles H₂(g)

grams H₂(g) = 3.05 moles x 2 grams/mole = 6.11 grams H₂(g)