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In Triangle EFG, the measure of G=90°, the measure of F=47°,

and GE = 50 feet. Find the length of EF to the nearest tenth
of a foot.

1 Answer

7 votes

Answer:

73.3

Explanation:

Using the SOH CAH TOA identity

EF = hypotenuse= x

FG = opposite

GE = adjacent = 50feet

Cos 47 = adj/hyp

Cos 47 = 50/x

x = 50/cos47

x = 50/0.6819

x = 73.32

hence the length of EF is 73.3 feet to the nearest tenth

User Arnav Gupta
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