126k views
15 votes
It takes 600 J of work to lifta crate straight up but 1,200 Jto pushthat crate up a ramp to the same height. What's the efficiency of the ramp?

User Eivanov
by
7.9k points

1 Answer

11 votes

Answer:

50 percent

Step-by-step explanation:

The efficiency of ramp can be found by using this formula

(Output work/input work)*100.

Amounts of work to lift up = 600j

Amount of work bro take up to same height = 1200j

Efficiency of ramp = (600j/1200j) * 100

= 0.5 x100

= 50 percent

Therefore from the calculations above, the efficiency of this ramp is 50 percent

User James Roper
by
7.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.