Question

Plz help

Elimination method

1.
3x-5y=3
4x-15=-21


2. 1000 tickets were sold for a school play. The regular price tickets were $5. Tickets for reserved seating was $2 more. The box office took in a total of $5300. How many tickets of each type were sold?

Answer 1

1. (6,3)

2. x = 850, y = 150

Explanation:

1. 3x-5y=3

4x-15y=-21

-9x +15y=-3 (multiply by -3)

4x-15y=-21

-5x=-30

x = 6

3(6)-5y=3

18-5y=3

-5y= -15

y= 3

so, x = 6, y = 3

2.

let x be regular

let y be reserved

x+y=1000

x= 5, y= 5+2=7 ("2 dollar more")

5x+7y=5300

x+y=1000

use the elimination method

x=850, y=150

so, the regular tickets were 850 and reserved tickets were 150 sold.