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Find the vertex. y=10x^2+3

User Idonnie
by
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2 Answers

5 votes

Final answer:

To find the vertex of the given parabola y = 10x^2 + 3, we use the formula -b / (2a), where a is the coefficient of x^2 and b is the coefficient of x. Plugging in the values, we find that the vertex is at (0, 3).

Step-by-step explanation:

The given equation is y = 10x^2 + 3.

To find the vertex, we can use the formula x = -b / (2a), where a is the coefficient of x^2 and b is the coefficient of x.

In this case, a = 10 and b = 0. Plugging these values into the formula, we get x = 0.

Substitute this value of x back into the equation to find the y-coordinate of the vertex. y = 10(0)^2 + 3 = 3.

Therefore, the vertex of the parabola represented by the equation is (0, 3).

User Suman Bogati
by
4.1k points
9 votes

Answer:

(h,k)

(0,3)

Step-by-step explanation:

User Andy Davis
by
4.1k points