Answer:
(-3, 0)
Explanation:
We are given two linear functions:

And we want to find the point at which the two lines intersect.
At the point the two lines intersect, their y-values will be the same. In other words, we can set their functions equal to each other and solve for x. Thus:

Substitute:

Solve for x. Subtracting x from both sides yields:

And subtracting 12 from both sides yields:

Thus, the x-coordinate of the point where the two lines intersect is:

To find the y-value, we can use either function. Using the second function, we acquire:

(You will obtain the same result if you use the first function. Try it!)
Thus, the point of intersection is (-3, 0).