Answer:
34176.5 torr
Step-by-step explanation:
It is given that :
Initial pressure,
torr
Initial volume,
![$V_1 = 650 \ cm^3$](https://img.qammunity.org/2022/formulas/chemistry/high-school/1gkn1s43tcqgmn7ubt0ey1qpe8koo87er0.png)
Initial temperature,
![$T_1 = 85^\circ C$](https://img.qammunity.org/2022/formulas/chemistry/high-school/syriinyz2un79609n0z9o8u8lf12wdstyz.png)
Final volume,
![$V_2 = 65 \ cm^3$](https://img.qammunity.org/2022/formulas/chemistry/high-school/gx4mbodgx9spx4l4yj6uwr73jfjsc93oe0.png)
Final temperature,
![$T_2 = 350^\circ C$](https://img.qammunity.org/2022/formulas/chemistry/high-school/q5xhedhopy3rbjgt3sttv3cmrx4mwwyksw.png)
Therefore, using the combined gas laws, we can write :
![$(P_1V_1)/(T_1)=(P_2V_2)/(T_2)$](https://img.qammunity.org/2022/formulas/chemistry/high-school/pv14ynygqip40qrupxhc44a54z19qj57hu.png)
Substituting the values, we get
![$(830 * 650)/(85)=(P_2* 65)/(350)$](https://img.qammunity.org/2022/formulas/chemistry/high-school/ddnfgufnf19i60l1238htrpcq8fk7vzs1b.png)
![$P_2 = (830 * 650 * 350)/(85 * 65)$](https://img.qammunity.org/2022/formulas/chemistry/high-school/gl8szcyge8lzdgxrmp3ctl62wrtfrlkeys.png)
= 34176.5 torr
So the new pressure is 34176.5 torr.