Question

Find all real zeros of the function
F(x)=x^3-7x^2+2x+40

Answer 1

zeros of F(x) are 1, 3 +
`√(13)`, -3 +
`√(13)`

Explanation:

You need to solve the equation F(x) = 0

`x^(3) - 7x^(2) + 2x +40 = (x - 1)(x^(2) - 6x - 4) = 0\\ x = 1 \\ or \\ x^(2) - 6x -4 = 0`

Now solve the quadratic equation above using the quadratic formula.

You should get

`3 + √(13) \\ -3 + √(13)`

So, the zeros of F(x) are 1, 3 +
`√(13)`, -3 +
`√(13)`