Question

Some please help!!!
i need it for now!!!!
PLEASE

Answer 1

r =√[3V/(π h)]

Explanation:

V = ⅓ × π r²h

=> multiplied by 3

3V = π r² h

=> find r²

r² = 3V/(π h)

=> find r

r =√[3V/(π h)]

Answer 2

`r=\sqrt{(3V)/(\pi h)}`

Explanation:

Given equation:

`V=(1)/(3) * \pi r^2 h`

To isolate
`r`, multiply both sides by 3:

`\implies V * 3=(1)/(3) * \pi r^2 h * 3`

`\implies 3V= \pi r^2 h`

Divide both sides by
`\pi h`:

`\implies (3V)/(\pi h)= (\pi r^2 h)/(\pi h)`

`\implies (3V)/(\pi h)=r^2`

Square root both sides:

`\implies √(r^2)=\sqrt{(3V)/(\pi h)}`

As the radius is positive only:

`\textsf{Apply radical rule} \quad √(a^2)=a, \quad a \geq 0`

`\implies r=\sqrt{(3V)/(\pi h)}`