How many moles of Al2O3 are contained in 45.1 g of Al2O3?

Zwhconst asked Feb 5, 2022

258,725 views

6 votes

Zwhconst asked Feb 5, 2022

2.9k points

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

12 votes

Answer:

0.44mol

Step-by-step explanation:

1mol/102g=xmol/45.1g

-> x=(45.1x1)/102

x=0.44mol

Zey answered Feb 9, 2022

by Zey

3.3k points

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers