Question

.

During the combustion of methane (CH4), one mole of methane gas combines with two moles of oxygen gas (O2) to produce one mole of carbon dioxide gas (CO2) and two moles of water vapor. Which of the following chemical equations correctly represents the combustion of methane described above?

Answer 1

22.4 L methane reacts with 44.8L of oxygen to give 44.8L of CO

2 and 22.4 L of water

Step-by-step explanation:

From the balanced reaction: One mole(or 1 molecule or 16 g) of CH

4

​

reacts with 2 moles (or 2 molecules or 64 g) of oxygen to give one mole (or 1 molecule or 44 g) of CO

2

​

and 2 mole (or 2 molecules or 36 g) of water.

For the gaseous system at STP:

22.4 L methane reacts with 44.8 L of oxygen to give 22.4 L of CO

2

​

and 44.8 L of water.

​

and 2 mole (or 2 molecules or 36 g) of water.

For the gaseous system at STP:

22.4 L methane reacts with 44.8 L of oxygen to give 22.4 L of CO

2

​

and 44.8 L of water.