Question

a. Find the value of sin2A, cos2A, tan2A and cot2A when sinA = 4/5 , cosA =4/5, tanA= 3/4 and cotA = 12/13​

Answer 1

Explanation:

Given,

SinA = 4/5

CosA =4/5

TanA= 3/4

CotA = 12/13

Sin²A = SinA²

Cos²A = CosA²

Tan²A = TanA²

Cot²A = CotA²

Therefore,

Sin²A = (4/5)²

Cos²A = (4/5)²

Tan²A = (3/4)²

Cot²A = (12/13)²

Sin²A = 16/25

Cos²A = 16/25

Tan²A = 9/16

Cot²A = 144/169

Answer 2

Explanation:

explanation is given in picture