Question

Consecutive integers are integers that

differ by one. You can represent
consecutive integers as x, X + 1,
x + 2 and so on. Write an equation
and solve to find three consecutive
integers whose sum is 33.

Answer 1

Answer: The three numbers are 10, 11, and 12.

10+11+12 = 33

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Work Shown:

• x = smallest number
• x+1 = middle number
• x+2 = largest number

Each is a positive whole number

Add them up and set the result equal to 33. Solve for x.

(x) + (x+1) + (x+2) = 33

3x+3 = 33

3x+3-3 = 33-3 .... subtract 3 from both sides

3x = 30

3x/3 = 30/3 ..... divide both sides by 3

x = 10

x+1 = 10+1 = 11

x+2 = 10+2 = 12

Note how 10+11+12 = 33 to help confirm our answer.