A ball is thrown into the air with a speed of 32 feet per second. The function h=32t - 16t^2 models the height of the ball after t seconds. How many seconds does it take for the…

Question

asked Feb 1, 2022 121k views

1 Answer

Colintheshots · Answer 1 · 2022-02-05T04:25:51+0000

Answer:

t = 1 s

Explanation:

The function models the height of the ball after t seconds is given by :

h=32t - 16t^2

We need to find how many seconds does it take for the ball to reach its maximum height.

For maximum height put dh/dt = 0

$(dh)/(dt)=(d)/(dt)(32t - 16t^2)\\=32-32t$

So,

32-32t = 0

t = 1

So, it will take 1 second to reach its maximum height.