Question

Suppose that the width of a certain rectangle is 1 inch more than one-fourth of its length. The perimeter of the rectangle is 52 inches. Find the length and width of the rectangle.

Answer 1

Length = 20

Width = 6

Explanation:

Let the length of the rectangle be l inch, so, its width

`w= ((1)/(4)l+1)`

So the perimeter equals:

`P= 2l+2w=2l+2((1)/(4)l+1)=2l+(1)/(2)l+2=(5)/(2)l+2`

`52= (5)/(2)l+2`

`50 = (5)/(2)l`
`100=5l`
`20 = l`

Hence width:

`w = ((1)/(4)l+1)`

`w=5+1 = 6`

Length = 20

Width = 6