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Working together, two pipes can fill a swimming pool in 4 hours. Working alone the larger pipe can fill the pool in 6 hours. How many hours would it take the smaller pipe working alone to fill the swimming pool.

User CKT
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1 Answer

7 votes

Answer:

12 hours

Explanation:

The computation of the number of hours does the smaller pipe takes for working alone is shown below:

Given that

Total time taken for both types is 4 hours

And, the larger pipe alone can take 6 hours

Now for the smaller pipe we assume x

So,


(1)/(4) = (1)/(6) + (1)/(x) \\\\(1)/(4) - (1)/(6) = (1)/(x) \\\\(6 - 4)/(24) = (1)/(x) \\\\(2)/(24) = (1)/(x) \\\\(1)/(12) = (1)/(x) \\\\

x = 12 hours

User Josephkibe
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