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Square ABCD has sides of length 15 ft. If the remaining part of the shape is a semicircle, what is the perimeter around the entire shape, to the nearest hundred?

A) 53.41 ft
B) 58.27 ft
C) 61.28 ft
D) 68.55 ft

1 Answer

2 votes

Answer:

68.55

Explanation:

C= 2πr

C=2 x 3.14 x 7.5 = 47.1 (Divide by 2 for half circle)

47.1 ÷ 2 = 23.55 + 15 + 15 + 15 = 68.55

User Benjamin James
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