1. Find the missing side lengths of the special right triangles. Leave your answers as radicals in simplest form 30° 9

Question

asked Sep 13, 2022 74.6k views

1 Answer

Roy Sharon · Answer 1 · 2022-09-19T16:52:21+0000

Answer:

a = 18 units

b = 9√3 units

Explanation:

By applying sine rule in the given triangle,

sin(30°) =
$\frac{\text{Opposite side}}{\text{Hypotenuse}}$

(1)/(2)=(9)/(a)

a = 18 units

Now apply cosine rule in the given triangle,

cos(30°) =
$\frac{\text{Adjacent side}}{\text{Hypotenuse}}$

(√(3))/(2)=(b)/(a)

(√(3))/(2)=(b)/(18)

b =
(18√(3) )/(2)

b =
9√(3) units