Question

If I initally have a gas at a pressure of 12 atm, a volume of 23 L, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?

Answer 1

Answer: 30 L

Explanation: Use the combined gas law: P1V1/T1 = P2V2/T2

We want V2, so rearrange:

V2 = V1(T2/T1)(P1/P2)

Note how I've grouped the temperature and pressure into ratios. This allows us to cancle those units quickly and gives a perspective on what we should expect. Enter the data:

V2 = (23L)*(0.6667)*(0.8571)

V2 = 29.6 L 30 L for 2 sig figs