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Age at BBM 2019 Question Group 'A Brief answer questions; 1. Integrate the following: S(ax? + 2bx + c)3/2(2xa + 2b) dx 2.



User Rasilvap
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1 Answer

9 votes
9 votes

If the integral is


\displaystyle \int (ax^2+2bx+c)^(3/2)(2ax+2b)\,\mathrm dx

substitute
u = ax^2+2bx+c and
\mathrm du=(2ax+2b)\,\mathrm dx. Then you end up with


\displaystyle \int u^(3/2)\,\mathrm du = \frac25u^(5/2) + C

which in terms of x is


\boxed{\frac25(ax^2+2bx+c)^(5/2) + C}

User Charles Mager
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