Question

case high school sold 120 tickets to the school play and took in $195 from ticket sales. if student tickets were $1 and adult tickets were $2, how many of each kind did they sell?

Answer 1

By solving a system of equations, we find that Case High School sold 45 student tickets and 75 adult tickets for the school play.

Step-by-step explanation:

The student question deals with a system of equations where Case High School sold a total of 120 tickets for a school play, generating $195. Assuming 'x' represents student tickets and 'y' represents adult tickets, we have two equations:

x + y = 120 (since the total number of tickets sold was 120)

• 1*x + 2*y = 195 (since student tickets cost $1 and adult tickets cost $2, and the total amount collected was $195)

By solving this system of equations, we can determine how many student and adult tickets were sold.

Steps to Solve:

1. Begin with the first equation: x + y = 120
2. Solve for one of the variables, for example, x = 120 - y
3. Substitute x in the second equation with the expression from step 2: 1*(120 - y) + 2*y = 195
4. Simplify and solve for y: 120 - y + 2*y = 195 which becomes y + 120 = 195
5. Therefore, y = 195 - 120, which means y = 75 (adult tickets)
6. To find x, substitute y back into the first equation: x + 75 = 120
7. Therefore, x = 120 - 75, which means x = 45 (student tickets)

Case High School sold 45 student tickets and 75 adult tickets.

Answer 2

Answer: student = 45 ticket sold, adult = 75 ticket sold.

Step-by-step explanation:

Assume that all the ticket sold were adult ticket:

120 x 2$ = 240$

Then:

240$ - 195$ = 45$

Calculate the difference between student ticket and adult ticket:

2$ - 1$ = 1$

Find the student ticket:

45$/1$ = 45

45 ticket sold is the student ticket.

Find adult ticket sold:

120 - 45 = 75

75 ticket sold is the adult ticket.

Check:

(45 x 1) + (75 x 2) = 195
45 + 150 = 195
195 = 195