Find the zeros of f(x)=-x^2+6x+27

Chuck Taylor asked Jul 20, 2022

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Chuck Taylor asked Jul 20, 2022

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14 votes

Answer:

Zeroes of this function are -3 and 9.

Explanation:

Using quadratic formula we have:

(-6 +-
$\sqrt{6^(2)-4(-1)(27) }$ ) / 2(-1)

= -3, 9

Austin Morton answered Jul 25, 2022

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