Answer:
ninth year
Explanation:
Given the general form of an exponential equation;
P = a(1 +r)^t
We can now write in this particular case;
y = 4 * 10^6(1 + 0.07)^t
The year in which y reaches 7 * 10^6 dollars is
7 * 10^6 = 4 * 10^6 (1 + 0.07)^t
7 * 10^6/4 * 10^6 = (1 + 0.07)^t
1.75 = (1 + 0.07)^t
ln(1.75)= ln(1 + 0.07)^t
ln(1.75) = t ln(1 + 0.07)
0.5596 = 0.06766t
t = 0.5596/0.06766
t = 8 years
So, in the ninth year;
y = 4 * 10^6 (1 + 0.07)^t
y = 4 * 10^6 (1 + 0.07)^9
y = 7.35 * 10^6
Hence, the player's earnings first exceed $7,000,000 in the ninth year.