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Solve for x round to the nearest tenth if necessary

Solve for x round to the nearest tenth if necessary-example-1

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Answer:

is shown below

Explanation:

We are given a side length and an angle

We know that the sine of an angle is the opposite divided by the adjacent side length. We will use this because the picture requires the opposite side length and we are given the adjacent side length.

We know that sin=opposite/adjacent

so we can use sin(39)= x/30

and now we can multiply both sides to single out x

30*sin(39) = x

calculate the value and that is your answer

User Farran
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