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10 votes
Given: ABC , BD is an
altitude to side AC, & D is a midpoint
Prove: AB BC

Given: ABC , BD is an altitude to side AC, & D is a midpoint Prove: AB BC-example-1
User ZXynK
by
8.5k points

2 Answers

6 votes

Answer:

Explanation:

BD is an altitude given

D is midpoint of AC given

BD ⊥ AC an altitude is a perpendicular segment

from a vertex to the opposite side

AD = DC because BD is a perpendicular bisector

BD = BD reflexive property

∠ADB ≅ ∠CDB because BD ⊥ AC

ΔADB ≅ ΔCDB SAS

AB ≅BC corresponding sides of congruent triangles

are congruent

User Deevee
by
9.4k points
8 votes

Answer:

steps below

Explanation:

BD⊥AC ∠ADB = ∠CDB = 90°

D is mid-point: AD = CD

BD = BD

ΔADB ≅ ΔCDB

AB = BC

User Neurix
by
8.9k points

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