Question

The present age of the father is twice the age of his daughter. Ten years ago, the

difference of their ages was 20 years find their present ages​

Answer 1

The father is 40 and the daughter is 20.

Explanation:

x - the present age of the daughter

2x - the present age of the fathter

x - 10 - the age of the daughter ten year ago

2x - 10 - the age of the fathter ten year ago

Father is older than his dauther, so:

2x - 10 = (x - 10) + 20

2x - 10 = x - 10 + 20

2x - 10 = x + 10 {subtract x from both sides}

x - 10 = 10 {add 10 to both sides}

x = 20

2x = 2·20 = 40