Question

\large -45\div9-\left(-5\right)=

Answer 1

−45÷9−(−5)

=−5−(−5)

=−5+5

=5−5

= 0

-> The answer will be 0.

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Answer 2

`\boxed{\underline{\bf \: ANSWER}}`

`\sf\large -45/9-\left(-5\right) \\ = \sf - 5 - ( - 5) \\ \sf= - 5 + 5 \\ \sf = 5 - 5 \\ = \boxed{\bf 0}`

-> The answer will be 0.

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Hope it helps.

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