Answer:
379.79 g of KCl
Step-by-step explanation:
The balanced equation for the reaction is given below:
Cl₂ + 2KBr —> Br₂ + 2KCl
Next, we shall determine the mass of Cl₂ that reacted and the mass of KCl produced from the balanced equation. This can be obtained as follow:
Molar mass of Cl₂ = 70.90 g/mol
Mass of Cl₂ from the balanced equation = 1 × 70.90 = 70.90 g
Molar mass of KCl = 74.55 g/mol
Mass of KCl from the balanced equation = 2 × 74.55 = 149.1 g
SUMMARY:
From the balanced equation above,
70.90 g of Cl₂ reacted to produce 149.1 g of KCl.
Finally, we shall determine the mass of KCl produced by the reaction of 180.6 g of Cl₂. This can be obtained as follow:
From the balanced equation above,
70.90 g of Cl₂ reacted to produce 149.1 g of KCl.
Therefore, 180.6 g of Cl₂ will react to produce = (180.6 × 149.1)/70.90 = 379.79 g of KCl.
Thus, 379.79 g of KCl were obtained from the reaction.