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Find the least common multiple of 15[[m]^[3]] and 12[[b]^[2]] .

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Answer:

60m³b²

Explanation:

We need to find the least common multiple of 15 m³ and 12 b².

Prime factorization of 15 m³ = 3×5×m³

Prime factorization of 12 b² = 3×2×2×b²

Common = 3×5×m³×2×2×b²

= 60m³b²

So, the least common multiple of 15 m³ and 12 b² is equal to 60m³b².

User Donni
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