Question

#12 don’t understand need help significantly

Answer 1

C. 8.80 mol H₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structure

• Reading a Periodic Table
• Moles

Stoichiometry

• Using Dimensional Analysis
• Analyzing Reactions RxN

Step-by-step explanation:

Step 1: Define

[RxN - Balanced] N₂ (g) + 3H₂ (g) → 2NH₃ (g)

[Given] 100 g 2NH₃

[Solve] moles H₂

Step 2: Identify Conversions

[RxN] 2 mol NH₃ (g) → 3 mol H₂ (g)

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

Molar Mass of NH₃ - 14.01 + 3(1.01) = 17.04 g/mol

Step 3: Stoich

1. [DA] Set up conversion:
   `\displaystyle 100 \ g \ NH_3((1 \ mol \ NH_3)/(17.04 \ g \ NH_3))((3 \ mol \ H_2)/(2 \ mol \ NH_3))`
2. [DA] Multiply/Divide [Cancel out units]:
   `\displaystyle 8.80282 \ mol \ H_2`