Answer:
5588.46 pence
Step-by-step explanation:
The following data were obtained from the question:
Power of 1st equipment (P₁) = 10 KW
Power of 2nd equipment (P₂) = 2.5 KW Power of 3rd equipment (P₃) = 600 W
Time (t) = 9 hours per day.
Cost per day = 7.9 pence per unit KWh
Cost for a week =?
Next, we shall convert 600 W to KW. This can be obtained as follow:
1000 W = 1 KW
Therefore,
600 W = 600 W × 1 KW / 1000 W
600 W = 0.6 KW
Next, we shall determine the total power consumed. This can be obtained as follow:
Power of 1st equipment (P₁) = 10 KW
Power of 2nd equipment (P₂) = 2.5 KW Power of 3rd equipment (P₃) = 0.6 KW
Total power (Pₜ) =?
Pₜ = P₁ + P₂ + P₃
Pₜ = 10 + 2.5 + 0.6
Pₜ = 13.1 KW
Next, we shall determine the total time of operation in a week. This can be obtained as follow:
From the question given above, we were told that:
1 day = 9 hours
Therefore,
6 days = 6 × 9 = 54 hours.
Thus, the total time of operation is 36 hours.
Finally, we shall determine the cost operating the three (3) equipment for a week (i.e 6 days). This can be obtained as follow:
Total power (Pₜ) = 13.1 KW
Total time (tₜ) = 54 hours
Cost per day (Cₔ) = 7.9 pence per unit KWh
Cost per week (Cᵥᵥ) =?
Cᵥᵥ = Pₜ × tₜ × Cₔ
Cᵥᵥ = 13.1 × 54 × 7.9
Cᵥᵥ = 5588.46 pence
Therefore, the cost operating the three (3) equipment for a week (i.e 6 days) is 5588.46 pence