Question

the weight of a girl is 400N .the area of each shoe with which she is standing is 40cm square . calculate the pressure exerted by her both feet?​

Answer 1

P=2*
`10^(5)`Pa

Step-by-step explanation:

P=P1+P2

P1=
`(F)/(A)`

Putting the values

P1=
`(400)/(40*10^(-4) )`

P1=1*
`10^(5)`

It is the pressure exerted by 1 feet

Pressure exerted by 2nd feet is also equal to the pressure exerted by 1st feet then

P2=1*
`10^(5)`

P=P1+P2

P=(1*
`10^(5)`)+(1*
`10^(5)`)

P=200000Pa

P=2*
`10^(5)` Pa