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2 votes
2 votes
Find the distance between the points (-6, – 7) and (5. – 7).

User KristiLuna
by
2.5k points

2 Answers

9 votes
9 votes

Answer:

11

Explanation:

d=√(5-(-6))²+(-7-(-7))²

d=√(11²+0²)

d=11

User Dloomb
by
3.2k points
12 votes
12 votes

Answer:


\boxed {\boxed {\sf d= 11}}

Explanation:

We are asked to find the distance between 2 points. We will use the distance formula.


d= \sqrt{ (x_2-x_1)^2+(y_2-y_1)^2

In this formula, (x₁ , y₁) and (x₂ , y₂) are the points. We are given the points (-6, -7) and (5, -7). If we match the value and the corresponding variable, we see that:

  • x₁ = -6
  • y₁ = -7
  • x₂ = 5
  • y₂ = -7

Substitute these values into the formula.


d= \sqrt{(5- -6)^2 + (-7--7)^2

Solve inside the parentheses. Remember that two back-to-back negative signs become a plus sign.

  • (5 - - 6) = (5 +6) = 11
  • ( -7 - - 7) = (-7 +7) = 0


d= \sqrt{ (11)^2+(0)^2

Solve the exponents.

  • (11)² = 11 * 11 = 121
  • (0)² = 0*0= 0


d= \sqrt{(121)+(0)

Add.


d= √(121)


d=11

The distance between (-6, -7) and (5, -7) is 11.

User Papahabla
by
2.8k points