Question

How many L are required to make 3.5 M hydrochloric acid using 1.1 moles?

Answer 1

0.31 L

General Formulas and Concepts:

Math

Pre-Algebra

1. Order of Operations: BPEMDAS
2. Brackets
3. Parenthesis
4. Exponents
5. Multiplication
6. Division
7. Addition
8. Subtraction

• Left to Right

Equality Properties

• Multiplication Property of Equality
• Division Property of Equality
• Addition Property of Equality
• Subtraction Property of Equality

Chemistry

Atomic Structure

• Moles

Aqueous Solutions

• Molarity = moles of solute / liters of solution

Equilibrium - Acid/Base

• Strong Acids
• Weak Acids
• Writing Acids

Step-by-step explanation:

Step 1: Define

[Given] 3.5 M HCl

[Given] 1.1 moles

[Solve] Liters solution

Step 2: Solve

1. Substitute in variables [Molarity]:
   `\displaystyle 3.5 \ M = (1.1 \ moles)/(x \ L)`
2. [Solution] Cross-Multiply [Equality Property]:
   `\displaystyle x \ L = (1.1 \ mol)/(3.5 \ M)`
3. [Solution] Divide:
   `\displaystyle x = 0.314286 \ L`

Step 3: Check

Follow sig fig rules and round. We are given 2 sig figs.

0.314286 L ≈ 0.31 L