Question

How many Grams of Nitrogen are in 2.086 x 10 9 G of nh4no3

Answer 1

730×10 6 g

Step-by-step explanation:

each one mole of NH4NO3 has 2 moles of nitrogen (2×14)

N NH4NO3

2×14 14+(4×1) +14+(3×16)

28 80

? 2.086 × 10 9

2.086× 10 9 ×28 ÷80 = 730 × 10 6 g of Nitrogen