Answer:
Jeweler should make 6 pins and 3 necklaces to maximize the profit.
Step-by-step explanation:
Demand for pins is 6 per week and profit is $400
Demand for necklaces is not known and profit is $100
Let x = pins and y = necklaces
The profit maximizing quantity equation will be :
Q = 400x + 100y
Constraints are labor hours and silver availability.
Labor hours available = 80 hours
Silver availability = 36 ounces
The constraint equation will be :
For labor hours : 8x + 10y ≤ 80
For silver : 2x + 6y ≤ 36
Solving the equation we will get maximum profit which is $2,700 and the quantity it should make is 6 pins and 3 necklaces to maximize the profit.