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39 votes
100 POINTS PLEASE HELP!!!!

100 POINTS PLEASE HELP!!!!-example-1
User Simeon
by
2.9k points

2 Answers

12 votes
12 votes

Answer:

a)F =1.8C +32

b) f(22) = 68 F

c) C = 5/9F -17 7/9

d) 28.3

slope= 5/9

B= -17 7/9

Explanation:

x1 y1 x2 y2

0 32 100 212

(Y2-Y1) (212)-(32)= 180 ΔY 180

(X2-X1) (100)-(0)= 100 ΔX 100

slope= 1 4/5

B= 32

Y =1.8X +32

User Thell
by
2.6k points
20 votes
20 votes

Answer:

a. F=1.8c + 32

b. 71.6 degrees Fahrenheit

c. c=(F-32)/1.8

d. 28.3 degrees Celcius

Explanation:

a. Given the two data points we can create an equation in slope-intercept form.

The y-intercept is 32

Slope can be found by doing 212-32/100-0 = 180/100 = 1.8

F=1.8c + 32

b. We can use this formula to solve for Fahrenheit

F=1.8(22)+32

F=71.6 degrees

c. Isolate c

F-32=1.8c

(F-32)/1.8=c

d. We can use this formula to solve for Celcius

(83-32)/1.8=c

c= 28.3333333 degrees

We can round that to 28.3 degrees Celcius

User Qris
by
2.4k points