Question

Slove the simoltanous equation by using substitution or elimination method 5x-3y=1 3x+2y=1
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Answer 1

By substitution method

5x - 3y =1

3x + 2y = 1

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`5x - 3y = 1 \\ 5x = 1 + 3y \\ x = (1 + 3y)/(5)`

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`3x + 2y = 1 \\ 3( (1 + 3y)/(5) ) + 2y = 1 \\ (3 + 9y)/(5) + 2y = 1 \\ (3 +9y + 10y)/(5) = 1 \\ (3 + 19y)/(5) = 1 \\ 3 + 19y = (1)(5) \\ 3 + 19y = 5 \\ 19y = 5 - 3 \\ 19y = 2 \\ y = (2)/(19)`

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`x = (1 + 3y)/(5) = (1 + 3 (2)/(19) )/(5) \\ x = (1 + (6)/(19) )/(5) = ( (19 + 6)/(19) )/(5) = ( (25)/(19) )/(5) \\ x = (25)/(19) / 5 \\ x = (25)/(19) * (1)/(5) \\ x = (5)/(19)`

I hope I helped you^_^