Question

PLEASE HELP!!!!!!!!!!! A clown has two performances today, in cities A and B, which are 240 km apart. The clown drives from City A to City B at a certain speed and performs. On his way back to City A, he drives half the distance at the same speed as before, but then increases his speed by 10 km/h to be on time for his performance in City A. Thus, the drive from B to A takes 2/5 of an hour less than the drive from A to B. At what speed does the clown drive from A to B?

Answer 1

Answer: 50 km/hr

240 = rt

120 = rt1

120 = (r+10)t2

t1 + t2 = t - 2/5 ==> t2 = 1/2 t - 2/5

So you get

240 = rt

120 = (r + 10)(1/2 t - 2/5)

Solve the system

You het 50 km/hr