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Please help my daughter has been stuck on this for the pass hour now

Please help my daughter has been stuck on this for the pass hour now-example-1
User Munter
by
4.9k points

2 Answers

4 votes

Answer:

Problem 1:

Coefficients are : 3 & 2

Variables are: w & b

Number of terms: 2

Constant: none

Problem 2:

Coefficients are : 6 & -2

Variables are: xy & c

Number of terms: 3

Constant: 4

Problem 3:

Coefficients are :
(2)/(3) & -3

Variables are: y & p

Number of terms: 2

Constant: none

Explanation:

Okay, lets break this down.

An Algebraic expression is not meant to be solved, but rather used to determine the various components inside of it to better understand how to solve equations later on. Although for now lets look at these problems. :

A Coefficient in terms of algebra, is the number before a variable. In other terms, a coeffiecient is the number before the letter such as 3w. Looking at 3w we see that there are two parts: 3, and w.

The number 3 is the coefficient while the variable is the letter w. Variables are always the letters.

Variable: A letter used to determine an unknown value such as x

Now a term is a single mathematical expression. It may be a single number (positive or negative), or a single variable ( a letter). (Can also be a coeffient with a variable multiplied or divided by one another as such :


3w = 3*w\\(3)/(w) = 3 / w

Some terms contain variables with a number in front of them. The number in front of a term is called a coefficient.

Now with that said, a constant is a number on its own, or sometimes a letter such as a, b or c to stand for a fixed number. Example: in "x + 5 = 9", 5 and 9 are constants.

With all of that said, lets look at the problems given:

Problem 1:

Coefficients are : 3 & 2

Variables are: w & b

Number of terms: 2

Constant: none

Problem 2:

Coefficients are : 6 & -2

Variables are: xy & c

Number of terms: 3

Constant: 4

Problem 3:

Coefficients are :
(2)/(3) & -3

Variables are: y & p

Number of terms: 2

Constant: none

I would be happy to help you again in the future, and hope that this provide you with some clarification. Have a nice day!

Please help my daughter has been stuck on this for the pass hour now-example-1
User Martijn Ten Hoor
by
6.0k points
6 votes

Answer:

algebraic expression: 3x + 2b

coefficients: 3 and 2

variables: w and b

# of terms: 2

constant: 0

algebraic expression: 6xy - 2c + 4

coefficients: 6 and -2

variables: x, y, and c

# of terms: 3

constant: 4

algebraic expression: 2/3 y - 3p

coefficients: 2/3 and -3

variables: y and p

# of terms: 2

constant: 0

User Bouvierr
by
5.5k points
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