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9 votes
9 votes
The area and perimeter is needed

The area and perimeter is needed-example-1
User Dickie
by
3.3k points

2 Answers

20 votes
20 votes

Answer:

Perimeter = 30 + 4
\pi ≈42.56 cm

Area = 88 - 8
\pi ≈ 62.88 cm^2

Explanation:

area of rectangle = 11* 8 = 88

Perimeter of rectangle = 38

perimeter of circle = 2
\pi4 = 8
\pi \\

area of circle =
\pi 4^(2) = 16
\pi

User Wickdninja
by
3.2k points
27 votes
27 votes

Answer:

Explanation:

Area of shaded region = Area of rectangle - area of semi circle

Rectangle:

length = 11 cm

Width = diameter of circle = 4 + 4 = 8 cm

Area 1 = length * width

= 11 * 8

= 88 sq. cm

Circle:

radius = r = 4 cm

Area of semicircle =
(1)/(2)\pi r^(2)\\


=(1)/(2)*3.14*4*4\\\\= 25.12 \ cm^(2)

Circumference of semicircle =
(2\pi r)/(2)=\pi r

= 3.14 * 4

= 12.56 cm

Area of the shaded region = 88 - 25.12 = 62.88 = 63 square cm

Perimeter of shaded region = 11 + 8 + 11 + circumference of semicircle

= 11 + 8 + 11 + 12.56

= 42.56

= 43 cm

User Mattandrews
by
2.9k points